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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Tìm ƯCLN và BCNN của các số sau a) 12; 15; 18 b) 24; 36; 150 c) 72; 108; 150 d) 45; 60; 105 :)

Toán Lớp 6: Tìm ƯCLN và BCNN của các số sau
a) 12; 15; 18
b) 24; 36; 150
c) 72; 108; 150
d) 45; 60; 105
🙂

Comments ( 2 )

  1. a) Ta có :
    12=2^2 .3
    15=3.5
    18=3^2 .2
    =>\text{ƯCLN}_{(12,15,18)}=3
           \text{BCNN}_{(12,15,18)}=2^2 .3^2 .5=180
    b) Ta có :
    24=2^3 .3
    36=2^2 .3^2
    150=2.3.5^2
    =>\text{ƯCLN}_{(24,36,150)}=2.3=6
           \text{BCNN}_{(24,36,150)}=2^3 .3^2 .5^2=1800
    c) Ta có :
    72=2^3 .3^2
    108=2^2 .3^3
    150=2.3.5^2
    =>\text{ƯCLN}_{(72,108,150)}=2.3=6
           \text{BCNN}_{(72,10,150)}=2^3 .3^3 .5^2=5400
    d) Ta có :
    45=3^2 .5
    60=2^2 .3.5
    105=3.5.7
    =>\text{ƯCLN}_{(45,60,105)}=3.5=15
           \text{BCNN}_{(45,60,105)}=2^2 .3^2 .5.7=1260
     

  2. Giải đáp:
     
    Lời giải và giải thích chi tiết:
     $a,$
    $Ta$ $có:$
    $12=2^{2}.3$
    $15=3.5$
    $18=2.3^{2}$
    $=>ƯCLN(12,15,18)=3$
         $BCLN(12,15,18)=2^{2}.3^{2}.5=4.9.5=180$
    $b,$
    $Ta$ $có:$
    $24=2^{3}.3$
    $36=2^{2}.3^{2}$
    $150=2.3.5^{2}$
    $=>ƯCLN(24,36,150)=2.3=6$
         $BCNN(24,36,150)=2^{3}.3^{2}.5^{2}=8.9.25=1800$
    $c,$
    $Ta$ $có:$
    $72=2^{3}.3^{2}$
    $108=2^{2}.3^{3}$
    $150=2.3.5^{2}$
    $=>ƯCLN(72,108,150)=2.3=6$
         $BCNN(72,108,150)=2^{3}.3^{3}.5^{2}=5400$
    $d,$
    $Ta$ $có:$
    $45=3^{2}.5$
    $60=2^{2}.3.5$
    $105=3.5.7$
    $=>ƯCLN(45,60,105)=5$
         $BCNN(45,60,105)=2^{2}.3^{2}.5.7=4.9.5.7=1260$
    (Bài tham khảo)

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222-9+11+12:2*14+14 = ? ( )