Toán Lớp 6: tìm số tự nhiên n sao cho (2n+5) chia hết cho(n+1)
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Toán Lớp 6: tìm số tự nhiên n sao cho (2n+5) chia hết cho(n+1)
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2n+5⋮n+1 vì (n+1)⋮(n+1) => 2(n+1)⋮(n+1) => (2n+2)⋮(n+1) => (2n+5)-(2n+2)⋮(n+1) => (2n+5-2n-2)⋮(n+1) => 3⋮(n+1) => (n+1)∈Ư(3){1;3} => n∈{0;2} vậy n∈{0;2}