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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Tìm n ∈ N 5n+3 chia hết n-1 38-3n chia hết 1-n

Toán Lớp 6: Tìm n ∈ N
5n+3 chia hết n-1
38-3n chia hết 1-n

Comments ( 2 )

  1. Giải đáp+Lời giải và giải thích chi tiết:
     5n+3 \vdots n-1
    Có n-1 \vdots n-1
    5(n-1) \vdots n-1
    5n-5 \vdots n-1
    5n+3-(5n-5) \vdots n-1
    8 \vdots n-1
    ⇒ n-1 ∈ {1;2;4;8}
    ⇒ n ∈ {2;3;5;9}
    38-3n \vdots 1-n
    Có 1-n \vdots 1-n
    3(1-n) \vdots 1-n
    3-3n \vdots 1-n
    38-3n-(3-3n) \vdots 1-n
    35 \vdots 1-n
    ⇒ 1-n ∈ {1;5;7;35}
    mà n ∈ N
    ⇒ n=0

  2. 5n+3 vdots n-1
    =>(5n+3)/(n-1)=>(5(n-1))/(n-1)=(5n-5)/(n-1)=((5n+3)-(5n-5))/(n-1)=8/(n-1)
    =>8vdots n-1
    =>n-1 ∈ Ư(8)={±1;±2;±4;±8}
    =>n∈{2;3;5;0;-1;-3;9;-7}
    Vì n∈N=>n∈{0;2;3;5;9}
    38-3n vdots 1-n
    =>(38-3n)/(1-n)=(38-3n-3(n-1))/(1-n)=(38-3n-(3-3n))/(1-n)=35/(n-1)
    =>1-n∈Ư(35)={±1;±5;±7}
    =>n∈{0;2;-4;6;-6;8}
    Vì n∈N=>n∈{0;2;6;8}
     

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222-9+11+12:2*14+14 = ? ( )