Register Now

Login

Lost Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: tìm các số nguyên x,y sao cho (x+1).(y+4)=-7 và x

Toán Lớp 6: tìm các số nguyên x,y sao cho (x+1).(y+4)=-7 và x

Comments ( 2 )

  1. (x+1)(y+4)=-7(x;y∈ZZ)
    Ta có : -7=-1.7=7.(-1)=-7.1=1.(-7)
    Ta có bảng sau :
    $\begin{array}{|c|c|c|}\hline \text{x+1}&\text{-1}&\text{7}&\text{-7}&\text{1}\\\hline \text{y+4}&\text{7}&\text{-1}&\text{1}&\text{-7}\\\hline \text{x}&\text{-2}&\text{6}&\text{-8}&\text{0}\\\hline \text{y}&\text{3}&\text{-5}&\text{-3}&\text{-11}\\\hline\end{array}$
    Mà x<y=>(x;y)∈{(-2;3);(-8;-3)}
    Vậy (x;y)∈{(-2;3);(-8;-3)}

  2. x . y = -7 (x; y ∈ ZZ)
    => x . y = -7 . 1 = 7 . -1
    Vì: x < y
    => $\left[\begin{matrix} xy ∈ (-7; 1)\\ xy ∈ (-1; 7)\end{matrix}\right.$
    Vậy: xy ∈ (-7; 1) và xy ∈ (-1; 7)

Leave a reply

222-9+11+12:2*14+14 = ? ( )

About Ngọc Sa