Toán Lớp 6: Tìm BC(96:180)
1+1=
2043838401+103892=
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Toán Lớp 6: Tìm BC(96:180)
1+1=
2043838401+103892=
Comments ( 2 )
a, ta có:
96 = $2^{5}$ x 5
180 = $2^{2}$ x $3^{2}$ x 5
=> BCNN( 96, 180 ) = $2^{5}$ x $3^{2}$ x 5 = 1440
=> BC(96,180) = B(1440) = { 0; 1440; 2880; 4320; … }
b, 1+ 1 = 2
c, 2043838401 + 103892 = 2043942293
Như sau, ta có:
96 = 2 mũ 5 . 3
180 = 2² . 3² . 5
⇒BCNN (96;180) = 2 mũ 5 .5.3² = 1440
⇒BC(96;180) = B(1440) = { 0; 1440 ; 2880 ; …}
1 +1 = 2
2043838401 + 103892 = 2043942293