Toán Lớp 6: Thực hiện phép tính
a/ (-10)+101+10+(-1)
b/ (-2000).5+4.(-2000)-9.(-2000)
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Toán Lớp 6: Thực hiện phép tính
a/ (-10)+101+10+(-1)
b/ (-2000).5+4.(-2000)-9.(-2000)
Comments ( 2 )
$a)$ $\left(-10\right)+101+10+\left(-1\right)$
$=91+10+\left(-1\right)$
$=101+\left(-1\right)$
$=101-1$
$=100$
$b)$ $\left(-2000\right)\cdot 5+4\cdot \left(-2000\right)-9\cdot \left(-2000\right)$
$=\left[\left(-2000\right)\cdot \:5\right]+\left[4\left(-2000\right)\right]-\left[9\left(-2000\right)\right]$
$=-10000-8000-\left(-18000\right)$
$=-18000-\left(-18000\right)$
$=-18000+18000$
$=0$
a) ( -10 ) + 101 + 10 + ( -1 )
= [ ( -10 ) + ( -1 ) ] + ( 101 + 10 )
= ( -11 ) + 111
= 100
b) ( -2000 ). 5 + 4. ( -2000 ) – 9. (-2000 )
= (-2000 ). ( 5 + 4 – 9 )
= ( -2000 ). 0
= 0