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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Giải nhanh giúp em ạ. Bài 3 : Tìm x thuộc Z sao cho : a, 565 – 13 . x = 370 b, 198 – ( x + 4 ) = 120 c, 140 : (x – 8) = 7 d, x + 5 =

Tháng Một 30, 2023 Toán học 1 Comment 0 views

Toán Lớp 6: Giải nhanh giúp em ạ.
Bài 3 : Tìm x thuộc Z sao cho :
a, 565 – 13 . x = 370
b, 198 – ( x + 4 ) = 120
c, 140 : (x – 8) = 7
d, x + 5 = 20 – (12 – 7)
e) 4 . (x + 41) = 400
f) 89 – (73 – x) = 20
g) (x – 1)^2 = 1
o) (x + 7) – 25 = 13
h) x . (x – 1) = 0
i) (2x -16)^7 = 128
k) (x + 2) . (x – 4) = 0
l) 484 + x = -632 + ( -548)
m) ( – x ) + (-62) + (-46) = -14
n) 3 – (17 – x) = 289 – (36 + 289)

Comments ( 1 )

  1. thucquyenlan
    thucquyenlan
    30 Tháng Một, 2023 at 5:54 chiều
    Reply
    $a) 565 – 13 . x = 370$
    $⇔ 13 . x = 565 – 370$
    $⇔ 13 . x = 195$
    $⇔ x = 195 : 13$
    $⇔ x = 15$
    $b) 198 – ( x + 4 ) = 120$
    $⇔ x + 4 = 198 – 120$
    $⇔ x + 4 = 78$
    $⇔ x = 78 – 4$
    $⇔ x = 74$
    $c, 140 : (x – 8) = 7$
    $⇔ x – 8 = 140 : 7$
    $⇔ x – 8 = 20$
    $⇔ x = 20 + 8$
    $⇔ x = 28$
    $d, x + 5 = 20 – (12 – 7)$
    $⇔ x + 5 = 20 – 5$
    $⇔ x + 5 = 15$
    $⇔ x = 15 – 5 $
    $⇔ x = 10$
    $e) 4 . (x + 41) = 400$
    $⇔ x + 41 = 400 : 4$
    $⇔ x + 41 = 100$
    $⇔ x = 100 – 41 $
    $⇔ x = 59$
    $f) 89 – (73 – x) = 20$
    $⇔ 73 – x = 89 – 20$
    $⇔ 73 – x = 69$
    $⇔ x = 73 – 69$
    $⇔ x = 4$
    $g) (x – 1)^{2} = 1$
    $⇔ ( x – 1 )^{2} = 1^{2}$
    $⇔ x – 1 = 1$
    $⇔ x = 1 + 1$
    $⇔ x = 2$
    $o) (x + 7) – 25 = 13$
    $⇔ x + 7 = 13 + 25$
    $⇔ x + 7 = 38$
    $⇔ x = 38 – 7$
    $⇔ x = 31
    $h) x . (x – 1) = 0$
    $⇔ \left[ \begin{array}{}x=0\\x – 1=0\end{array} \right.$
    $⇔ \left[ \begin{array}{}x=0\\x = 0 + 1\end{array} \right.$
    $⇔ \left[ \begin{array}{}x=0\\x = 1\end{array} \right.$
    $i) (2x -16)^7 = 128$
    $⇔ ( 2x – 16 )^{7} = 2^{7}$
    $⇔ 2x – 16 = 2$
    $⇔ 2x = 2 + 16$
    $⇔ 2x = 18$
    $⇔ x = 18 : 2$
    $⇔ x = 9$
    $k) (x + 2) . (x – 4) = 0$
    $⇔\left[ \begin{array}{l}x + 2=0\\x – 4 = 0\end{array} \right.$
    $⇔\left[ \begin{array}{l}x=0-2\\x=0+4\end{array} \right.$
    $⇔ \left[ \begin{array}{l}x=-2\\x=4\end{array} \right.$
    $l) 484 + x = -632 + ( -548)$
    $⇔ 484 + x = – 1180$
    $⇔ x = – 1180 – 480$
    $⇔ x = – 1660$
    $m) ( – x ) + (-62) + (-46) = -14$
    $⇔ – x – 62 – 46 = – 14$
    $⇔ – x – 108 = – 14$
    $⇔ – x = – 14 + 108$
    $⇔ – x = 94$
    $⇔ x = 94 : ( – 1 )$
    $⇔ x = – 94$
    $n) 3 – (17 – x) = 289 – (36 + 289)$
    $⇔ 3 – ( 17 – x ) = 289 – 325$
    $⇔ 3 – ( 17 – x ) = – 36$
    $⇔ 17 – x = 3 – ( – 36 )$
    $⇔ 17 – x = 39$
    $⇔ x = 17 – 39$
    $⇔ x = – 22$
    ⇔
    ⇔

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222-9+11+12:2*14+14 = ? ( )

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