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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: chứng minh rằng A=2012+2012^2+2012^3+2012^4+…+2012^11+2012^13 chia hết cho 2013

Home/ Toán Lớp 6: chứng minh rằng A=2012+2012^2+2012^3+2012^4+…+2012^11+2012^13 chia hết cho 2013

Toán Lớp 6: chứng minh rằng A=2012+2012^2+2012^3+2012^4+…+2012^11+2012^13 chia hết cho 2013

Tháng Chín 22, 2022 Toán học 1 Comment 0 views

Toán Lớp 6: chứng minh rằng A=2012+2012^2+2012^3+2012^4+…+2012^11+2012^13 chia hết cho 2013

Comments ( 1 )

  1. thaolanphuobg
    thaolanphuobg
    22 Tháng Chín, 2022 at 3:03 sáng
    Reply
    $\text{A = 2012 + $2012^{2}$ + $2012^{3}$ + $2012^{4}$ + … + $2012^{13}$ }$
    $\text{$\Longrightarrow$ 2012A = 2013($2012^{2}$ + $2012^{3}$ + … + $2012^{14}$)}$
    $\text{$\Longrightarrow$ 2012A – A = 2013($2012^{2}$ + $2012^{3}$ + … + $2012^{14}$) – (2012 + $2012^{2}$ + $2012^{3}$ + … + $2012^{13}$)}$
    $\text{$\Longrightarrow$ 2011A = 2013($2012^{14}$ – 2012)}$
    $\text{Vậy A = $\dfrac{2012^{14} – 2012}{2011}$ $\vdots$ 2013}$

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222-9+11+12:2*14+14 = ? ( )

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