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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: Cho A=2+2 mũ 2+2 mũ 3+…+2 mũ 60.Chứng tỏ rằng: a,A chia hết cho 3 b,A chia hết cho7 c,Achia hết cho 5

Toán Lớp 6: Cho A=2+2 mũ 2+2 mũ 3+…+2 mũ 60.Chứng tỏ rằng:
a,A chia hết cho 3
b,A chia hết cho7
c,Achia hết cho 5

Comments ( 2 )

  1.  a) 2 + 2^2 + 2^3 + … + 2^{60}
    = ( 2 + 2^2 ) + ( 2^3 + 2^4 ) + … + ( 2^{59} + 2^{60} )
    = 2( 1 + 2 ) + 2^3 (1+2) + … + 2^{59}(1 + 2 )
    = 3( 2 + 2^3 + 2^5 + … + 2^{59} ) \vdots 3
    b) 2 + 2^2 + 2^3 + … + 2^{60}
    = ( 2 + 2^2 + 2^3 ) + ( 2^4 + 2^5 + 2^6 ) + … + ( 2^{58} + 2^{59} + 2^{60}
    = 2(  1 + 2 + 2^2 ) + 2^4(1 + 2 + 2^2 ) + … + 2^{58}(1 + 2 + 2^2 )
    = 7( 2 + 2^4 + … + 2^{58} ) \vdots 7
    c) 2 + 2^2 + 2^3 + … + 2^{60}
    = ( 2 + 2^3 ) + ( 2^2 + 2^4 ) + … + ( 2^{58} + 2^{60} )
    = 2( 1 + 2^2 ) + 2^2(1 + 2^2 ) + … + 2^{58}(1 + 2^2 )
    = 5( 2 + 2^2 … + 2^{58} ) \vdots 5

  2. Giải đáp+Lời giải và giải thích chi tiết:
    $a)A=2+2 ^ 2+2 ^ 3+…+2 ^{60}\\=(2+2 ^ 2)+(2 ^ 3+2^4)+ . . . + (2^{59}+2 ^{60})\\=2.(1+2)+2^3.(1+2)+. . . +2^{59}.(1+2)\\=2.3+2^3.3+. . . +2^{59}.3\\=3.(2+2^4+.. . +2^{59})\vdots3\\Vậy \ A \ \vdots \ 3$
    $b)A=2+2 ^ 2+2 ^ 3+…+2 ^{60}\\=(2+2 ^ 2+2 ^ 3)+…+(2^{58}+2^{59}+2 ^{60})\\=2.(1+2+4)+…+2^{58}.(1+2+4)\\=2.7+. ..+2^{58}.7\\=7.(2+. . +2^{58})\vdots 7\\Vậy\ A\ \vdots \ 7$
    $c)A=2+2 ^ 2+2 ^ 3+…+2 ^{60}\\=(2+2^3)+(2^2+2^4)+. . .+(2^{58}+2^{60})\\=2.(1+4)+2^2.(1+4)+…+2^{58}.(1+4)\\=2.5+2^2.5+…+2^{58}.5\\=5.(2+2^2+… +2^{58})\vdots 5\\Vậy\ A\ \vdots \ 5$

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222-9+11+12:2*14+14 = ? ( )