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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: cho A = 1+4+4 mũ 2 + 4 mũ 3 + …+4 mũ 1999 + 4 mũ 2000 . chứng minh rằng A chia hết cho 21

Toán Lớp 6: cho A = 1+4+4 mũ 2 + 4 mũ 3 + …+4 mũ 1999 + 4 mũ 2000 . chứng minh rằng A chia hết cho 21

Comments ( 1 )

  1. A=1+4+4²+…+$4^{1999}$ +$4^{2000}$ 
    A=(1+4+4²)+(4³+$4^{4}$+$4^{5}$)+…+($4^{1998}$+$4^{1999}$+$4^{2000}$)
    A=[1×(1+4+4²)]+[4³+(1+4+4²)]+…..+[$4^{1998}$×(1+4+4²)]
    A=(1+4+4²)×[1+4³+…+$4^{1998}$]
    A=(1+4+16)×[1+4³+…+$4^{1998}$]
    A=(5+16)×[1+4³+…+$4^{1998}$]
    A=21 ×[1+4³+…+$4^{1998}$] $\vdots$ 21
    Vậy A $\vdots$ 21

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222-9+11+12:2*14+14 = ? ( )