Toán Lớp 6: Câu1: Tính hợp lý (nếu có thể)
a) (-45) + 176 + 45 + (-76)
b) 127 – ( 4.5^2 – 64: 2^3)
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Toán Lớp 6: Câu1: Tính hợp lý (nếu có thể)
a) (-45) + 176 + 45 + (-76)
b) 127 – ( 4.5^2 – 64: 2^3)
Comments ( 2 )
a)
( -45 ) + 176 + 45 + ( -76 )
= -45 + 176 + 45 – 76
= ( -45 + 45 ) + ( 176 – 76 )
= 0 + 100
= 100
b)
127 – ( 4. 5^2 – 64 : 2^3 )
= 127 – ( 4. 25 – 64 : 8 )
= 127 – ( 100 – 8 )
= 127 – 100 + 8
= 27 + 8
= 35
Giải đáp:
a) (-45) + 176 + 45 + (-76)
= [(-45) + 45] + [176 + (-76)]
= 0 + [+(176 – 76)]
= 0 + 100
= 100
b) 127 – (4 . $5^{2}$ – 64 : $2^{3}$)
= 127 – (4 . 25 – 64 : 8)
= 127 – (100 – 8)
= 127 – 92
= 35