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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: C.( 2x + 6 ) chia hết cho ( x+2 ) D.( 2x + 3 ) chia hết cho ( 3x + 2 )

Toán Lớp 6: C.( 2x + 6 ) chia hết cho ( x+2 )
D.( 2x + 3 ) chia hết cho ( 3x + 2 )

Comments ( 2 )

  1. c) 2x + 6 \vdots x + 2
    => 2x + 4 + 2 \vdots x + 2
    => 2(x+2) + 2\vdots x + 2
    => 2(x+2) \vdots x + 2
    => 2 \vdots x + 2
    => x + 2 ∈ Ư(2) = {±1;±2}
    => x ∈ {-1;-3;0;-4}
    Vậy x ∈ {-1;-3;0;-4} 
    d) (2x + 3) \vdots (3x + 2)
    => 3(2x+3) \vdots (3x + 2)
    => 6x + 9 \vdots 3x + 2
    => 6x + 4 + 5 \vdots 3x + 2
    => 2(3x+2) + 5 \vdots 3x + 2
    Do 2(3x+2) \vdots 3x + 2
    => 5 \vdots 3x + 2
    => 3x + 2 ∈ Ư(5) = {±1;±5} 
    => x ∈ {frac{-1}{3};-1;1;frac{-7}{3} 
    Vậy x ∈ {frac{-1}{3};-1;1;frac{-7}{3}} 

  2. c, 2x + 6 \vdots x + 2
    => 2x + 4 + 2 \vdots x + 2
    => 2(x + 2) + 2 \vdots x + 2
    Vì 2(x + 2) \vdots x + 2 nên 2 \vdots x + 2
    => x + 2 ∈ Ư (2) = {1 ; – 1 ; 2 ; – 2}
    => x ∈ {-1 ; – 3 ; 0 ; -4}
    d, 2x + 3 \vdots 3x + 2
    => 3(2x + 3) \vdots 3x + 2
    => 6x + 9 \vdots 3x + 2
    => 6x + 4 + 5 \vdots 3x + 2
    => 2(3x + 2) + 5 \vdots 3x + 2
    Vì 2(3x + 2) \vdots 3x + 2 nên 5 \vdots 3x + 2
    => 3x + 2 ∈ Ư (5) = {1 ; – 1 ; 5 ;  – 5}
    => 3x ∈ {-1 ; – 3 ; 3 ; – 7}
    => x ∈ {\frac{-1}{3} ; – 1 ; 1 ; \frac{-7}{3}}

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222-9+11+12:2*14+14 = ? ( )

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