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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: B=3-3^2+3^3-3^4+…+3^2013-3^2014+3^2015

Toán Lớp 6: B=3-3^2+3^3-3^4+…+3^2013-3^2014+3^2015

Comments ( 2 )

  1. $ 3B = 3^2 – 3^3 + 3^4 – 3^5 + …. + 3^{2014} – {3^2015} + {3^2016} $
    $ 3B + B = ( 3^2 – 3^3 + 3^4 – 3^5 + …. + 3^{2014} – {3^2015} + {3^2016} $ ) + ( 3 – 3^2 + 3^3 – 3^4 – … + 3^{2013} – 3^{2014} + 3^{2015} ) $
    $ 4B = ( 3 +3^{2016} ) + ( 3^2 – 3^2 ) + ( 3^3 – 3^3 ) + … + ( 3^{2014} – 3^{2014} ) + ( 3^{2015} – 3^{2015} ) $ 
    $ 4B = 3 + 3^{2016} ⇒ B = ( 3+3^{2016} ) : 4 $
     

  2. Giải đáp:
    $B=\dfrac{3^{2016}+3}4$.
    Lời giải và giải thích chi tiết:
    $\begin{array}{l}B=3-3^2+3^3-3^4\ +\,.\!.\!.+\ 3^{2013}-3^{2014}+3^{2015}\\\Rightarrow 3B=3.(3-3^2+3^3-3^4\ +\,.\!.\!.+\ 3^{2013}-3^{2014}+3^{2015})\\\Rightarrow 3B=3^2-3^3+3^4-3^5\ +\,.\!.\!.+\ 3^{2014}-3^{2015}+3^{2016}\\\Rightarrow 3B+B=(3^2-3^3+3^4-3^5\ +\,.\!.\!.+\ 3^{2014}-3^{2015}+3^{2016})+(3-3^2+3^3-3^4\ +\,.\!.\!.+\ 3^{2013}-3^{2014}+3^{2015})\end{array}\\\Rightarrow 4B=3^{2016}+3\\\Rightarrow B=\dfrac{3^{2016}+3}4$

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222-9+11+12:2*14+14 = ? ( )

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