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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: (3x + 2) chia hết cho (x – 3) Tìm số nguyên x

Toán Lớp 6: (3x + 2) chia hết cho (x – 3)
Tìm số nguyên x

Comments ( 2 )

  1. Ta có :
    ⇔ 3x + 2 $\vdots$ x – 3
    ⇔ 3x – 9 + 11 $\vdots$ x – 3
    ⇔ 3( x – 3 ) + 11 $\vdots$ x – 3
    Mà x – 3 $\vdots$ x – 3
    => 3( x – 3 ) $\vdots$ x – 3
    => 11 $\vdots$ x – 3
    => x – 3 ∈ Ư(11) = { ±1; ±11 }
    Với x – 3 = 1
    => x       = 4
    Với x – 3 = -1
    => x       = 2
    Với x – 3 = 11
    => x       = 14
    Với x – 3 = -11
    => x       = -8
    Vậy x ∈ { 2; 4; -8; 14 }

  2. Answer
    $\text{Ta có:}$ 3x + 2 \vdots x – 3
    $\text{Mà:}$ x – 3 \vdots x – 3
    => 3 . (x – 3) \vdots x – 3
    => 3x – 9 \vdots x – 3
    $\text{Lập hiệu}$
    (3x + 2) – (3x – 9)
    = 3x + 2 – 3x + 9
    = (3x – 3x) + (2 + 9)
    = 11 \vdots x – 3
    $\text{Vì}$ x \in ZZ
    => x – 3 \in Ư(11) = {+-1 ; +-11}
    $\text{Lập bảng giá trị}$
    $\begin{array}{|c|c|c|}\hline x-3&1&11&-1&-11\\\hline x&4&14&2&-8\\\hline \text{Thử lại}&\text{TM}&\text{TM}&\text{TM}&\text{TM}\\\hline\end{array}$
    $\text{Vậy}$ x \in {4 ; 14 ; 2 ; -8}

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222-9+11+12:2*14+14 = ? ( )

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