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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: 1/ x.(x + 7) = 0 2/ (x + 12).(x-3) = 0 3/ (-x + 5).(3 – x ) = 0 4/ x.(2 + x).( 7 – x) = 0 5/ (x – 1).(x +2).(-x -3) = 0 6/ (-3)=

Home/ Toán Lớp 6: 1/ x.(x + 7) = 0 2/ (x + 12).(x-3) = 0 3/ (-x + 5).(3 – x ) = 0 4/ x.(2 + x).( 7 – x) = 0 5/ (x – 1).(x +2).(-x -3) = 0 6/ (-3)=

Toán Lớp 6: 1/ x.(x + 7) = 0 2/ (x + 12).(x-3) = 0 3/ (-x + 5).(3 – x ) = 0 4/ x.(2 + x).( 7 – x) = 0 5/ (x – 1).(x +2).(-x -3) = 0 6/ (-3)=

Tháng Tám 13, 2022 Toán học 2 Comments 0 views

Toán Lớp 6: 1/ x.(x + 7) = 0
2/ (x + 12).(x-3) = 0
3/ (-x + 5).(3 – x ) = 0
4/ x.(2 + x).( 7 – x) = 0
5/ (x – 1).(x +2).(-x -3) = 0
6/ (-3)= -12

Comments ( 2 )

  1. ngoclanhoa
    ngoclanhoa
    13 Tháng Tám, 2022 at 5:17 chiều
    Reply
    1,
    x.(x+7)=0
    =>\(\left[ \begin{array}{l}x=0\\x+7=0\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=0\\x=-7\end{array} \right.\) 
    Vậy x=0; x=-7
    $\\$
    2,
    (x+12).(x-3)=0
    =>\(\left[ \begin{array}{l}x+12=0\\x-3=0\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=-12\\x=3\end{array} \right.\) 
    Vậy x=-12; x=3
    $\\$
    3,
    (-x+5).(3-x)=0
    =>\(\left[ \begin{array}{l}-x+5=0\\3-x=0\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}-x=-5\\x=3\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=5\\x=3\end{array} \right.\) 
    Vậy x=5; x=3
    $\\$
    4,
    x.(2+x).(7-x)=0
    =>\(\left[ \begin{array}{l}x=0\\2+x=0\\7-x=0\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=0\\x=-2\\x=7\end{array} \right.\) 
    Vậy x=0; x=-2; x=7
    $\\$
    5,
    (x-1).(x+2).(-x-3)=0
    =>\(\left[ \begin{array}{l}x-1=0\\x+2=0\\-x-3=0\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=1\\x=-2\\-x=3\end{array} \right.\) 
    =>\(\left[ \begin{array}{l}x=1\\x=-2\\x=-3\end{array} \right.\) 
    Vậy x=1; x=-2; x=-3
    $\\$
    6,
    (-3).x=-12
    =>x=(-12):(-3)
    =>x=4
    Vậy x=4

  2. hauthanhyen98
    hauthanhyen98
    13 Tháng Tám, 2022 at 5:17 chiều
    Reply
    Giải đáp + Lời giải và giải thích chi tiết:
    1, x . (x + 7) = 0
    $\left[\begin{matrix} x = 0\\ x + 7 = 0\end{matrix}\right.$
    $\left[\begin{matrix} x = 0\\ x = 0 – 7 = -7\end{matrix}\right.$
    Vậy x ∈ {-7 ; 0}
    2, (x + 12) . (x – 3) = 0
    $\left[\begin{matrix} x + 12 = 0\\ x – 3 = 0\end{matrix}\right.$
    $\left[\begin{matrix} x = 0 – 12 = -12\\ x = 0 + 3 = 3\end{matrix}\right.$
    Vậy x ∈ {-12; 3}
    3, (-x + 5) . (3 – x) = 0
    -> $\left[\begin{matrix} -x + 5 = 0\\ 3 – x = 0\end{matrix}\right.$
    -> $\left[\begin{matrix} 5 – x = 0\\ 3 – x = 0\end{matrix}\right.$
    -> $\left[\begin{matrix} x = 5 – 0 = 5\\ x = 3 – 0 = 3\end{matrix}\right.$
    Vậy x ∈ {3 ; 5}
    4, x . (2 + x) . (7 – x) = 0
    TH1:
    x = 0
    TH2:
    2 + x = 0
    -> x = 0 – 2
    -> x = -2
    TH3:
    7 – x = 0
    -> x = 7 – 0
    -> x = 7
    Vậy x ∈ {-2 ; 0 ; 7}
    5, (x – 1) . (x + 2) . (-x – 3) = 0
    TH1:
    x – 1 =0
    -> x = 0 + 1
    -> x = 1
    TH2:
    x + 2 = 0
    -> x = 0 – 2
    -> x = -2
    TH3:
    -x – 3 = 0
    -> -x = 0 + 3
    -> -x = 3
    Vậy x ∈ {-3;-2;1}
    6, (-3) . x = – 12
    -> x = (-12) : (-3)
    -> x = 4
    $@Miru$

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222-9+11+12:2*14+14 = ? ( )

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