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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 5: So sánh 2 phân số sau bằng cách nhanh nhất 98765432/99765433 và 10234567/11234568

Toán Lớp 5: So sánh 2 phân số sau bằng cách nhanh nhất
98765432/99765433 và 10234567/11234568

Comments ( 2 )

  1. \text {@Luffy Cat}
    Ta có: 1 – $\dfrac{98765432}{99765433}$ = $\dfrac{1000001}{99765433}$
              1 – $\dfrac{10234567}{11234568}$ = $\dfrac{1000001}{11234568}$
     Vì $\dfrac{1000001}{99765433}$ < $\dfrac{1000001}{11234568}$ nên $\dfrac{98765432}{99765433}$ > $\dfrac{10234567}{11234568}$
    Vậy $\dfrac{98765432}{99765433}$ > $\dfrac{10234567}{11234568}$

  2. 98765432/99765433 = 1 – 10000001/99765433
    10234567/11234568 = 1 – 10000001/11234568
    Vì 10000001/99765433 < 10000001/11234568 => 98765432/99765433 > 10234567/11234568
    #dtkc

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222-9+11+12:2*14+14 = ? ( )