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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 5: A = 3 mũ 2 . 4 mũ 3 – 3 mũ 2 + 333 C = 5 . 4 mũ 3 + 2 mũ 4 . 5 + 41 A = 2 mũ 5 . 5 mũ 2 – 8 mũ 2 – 7 C= 11 .2 mũ 4 + 6 mũ

Toán Lớp 5: A = 3 mũ 2 . 4 mũ 3 – 3 mũ 2 + 333
C = 5 . 4 mũ 3 + 2 mũ 4 . 5 + 41
A = 2 mũ 5 . 5 mũ 2 – 8 mũ 2 – 7
C= 11 .2 mũ 4 + 6 mũ 2 . 19 + 40
B = 5 . 3 mũ 2 +4 . 3 mũ 2f

Comments ( 2 )

  1. a)
    A = 3^2 . 4^3 – 3^2 + 333
    A = 9 . 64 – 9 + 333
    A = 576 – 9 + 333
    A = 567 + 333
    A = 900 hay 30^2
    b)
    C = 5 . 4^3 + 2^4 . 5 + 41
    C = 5 . 64 + 16 . 5 + 41
    C = 320 + 80 + 41
    C = 400 + 41
    C = 441 hay 21^2
    c)
    A = 2^5 . 5^2 – 8^2 – 7
    A = 32 . 25 – 64 – 7
    A = 800 – 64 – 7
    A = 736 – 7
    A = 729 hay 3^6
    d)
    C= 11 .2^4 + 6^2 . 19 + 40
    C= 11. 16 + 36 . 19 + 40
    C= 176 + 684 + 40
    C= 860 + 40
    C= 900 hay 30^2
    e)
    B = 5 . 3^2 + 4 . 3^2
    B = 3^2 (5+4)
    B = 9 . 9
    B = 81 hay 9^2

  2. Giải đáp + Lời giải và giải thích chi tiết:
    A = $3^{2}$ . $4^{3}$ – $3^{2}$ + $333^{}$
    A = $9^{}$ . $64^{}$ – $9^{}$ + $333^{}$ 
    A = $576^{}$ – $9^{}$ + $333^{}$
    A = $567^{}$ + $333^{}$ 
    Vậy A = $900^{}$
    .
    C = $5^{}$ . $4^{3}$ + $2^{4}$ . $5^{}$ + $41^{}$
    C = $5^{}$ . $64^{}$ + $16^{}$ . $5^{}$ + $41^{}$ 
    C = $320^{}$ + $80^{}$ + $41^{}$ 
    C = $400^{}$ + $41^{}$ 
    Vậy C = $441^{}$ 
    .
    A = $2^{5}$ . $5^{2}$ – $8^{2}$ – $7^{}$
    A = $32^{}$ . $25^{}$ – $64^{}$ – $7^{}$
    A = $800^{}$ – $64^{}$ – $7^{}$
    A = $736^{}$ – $7^{}$
    Vậy A = $729^{}$ 
    .
    C = $11^{}$ . $2^{4}$ + $6^{2}$ . $19^{}$ + $40^{}$
    C = $11^{}$ . $16^{}$ + $36^{}$ . $19^{}$ + $40^{}$
    C = $176^{}$ + $684^{}$ + $40^{}$
    C = $860^{}$ + $40^{}$
    Vậy C = $900^{}$ 
    .
    B = $5^{}$ . $3^{2}$ + $4^{}$ . $3^{2}$
    B = $5^{}$ . $9^{}$ + $4^{}$ . $9^{}$
    B = $45^{}$ + $36^{}$
    Vậy B = $81^{}$ 
    #Regina (●’◡’●)
    #Chúc cậu học tốt nè :>
     

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222-9+11+12:2*14+14 = ? ( )

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