Toán Lớp 11: sin5x=-$\frac{\sqrt[]{3}}{2}$
sin(x/2-$20^{o}$ )=0
cos2x=-$\frac{1}{2}$
cos(2x$-10^{o}$ )=$\frac{-\sqrt[]{2} }{2}$
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Toán Lớp 11: sin5x=-$\frac{\sqrt[]{3}}{2}$
sin(x/2-$20^{o}$ )=0
cos2x=-$\frac{1}{2}$
cos(2x$-10^{o}$ )=$\frac{-\sqrt[]{2} }{2}$
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