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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 11: các nghiệm của tan(x – pi/6)=căn3

Toán Lớp 11: các nghiệm của tan(x – pi/6)=căn3

Comments ( 2 )

  1. ~rai~
    \(\tan\left(x-\dfrac{\pi}{6}\right)=\sqrt{3}\quad(1)\\ĐKXĐ:\cos\left(x-\dfrac{\pi}{6}\right)\ne 0\\\Leftrightarrow x-\dfrac{\pi}{6}\ne \dfrac{\pi}{2}+m\pi\\\Leftrightarrow x\ne \dfrac{2\pi}{3}+m\pi.(m\in\mathbb{Z})\\(1)\Leftrightarrow x-\dfrac{\pi}{6}=\dfrac{\pi}{3}+k\pi\\\Leftrightarrow x=\dfrac{\pi}{2}+k\pi.(k\in\mathbb{Z})\\\text{Vậy S=}\left\{\dfrac{\pi}{2}+k\pi\Big|k\in\mathbb{Z}\right\}.\)

  2. Điều kiện xác định:
    $\begin{array}{l} \cos \left( {x – \dfrac{\pi }{6}} \right) \ne 0\\  \Leftrightarrow x – \dfrac{\pi }{6} \ne \dfrac{\pi }{2} + k\pi  \Leftrightarrow x \ne \dfrac{{2\pi }}{3} + k\pi \left( {k \in \mathbb Z} \right) \end{array}$
    $\begin{array}{l}
    \tan \left( {x – \dfrac{\pi }{6}} \right) = \sqrt 3 \\
     \Leftrightarrow x – \dfrac{\pi }{6} = \dfrac{\pi }{3} + k\pi \\
     \Leftrightarrow x = \dfrac{\pi }{2} + k\pi \left( {k \in \mathbb Z} \right)
    \end{array}$
     

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222-9+11+12:2*14+14 = ? ( )

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