Toán Lớp 10: GPT: $\sqrt{x-1}+2\sqrt{x^2-9}=10$
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Toán Lớp 10: GPT: $\sqrt{x-1}+2\sqrt{x^2-9}=10$
Comments ( 2 )
<=>(sqrt(x-1)-2)+(2sqrt(x^2-9)-8)=0
<=>(x-1-4)/(sqrt(x-1)+2)+(2(x^2-9-16))/(sqrt(x^2-9)+8)=0
<=>(x-5)/(sqrt(x-1)+2)+(2(x-5)(x+5))/(sqrt(x^2-9)+8)=0
<=>(x-5)(1/(sqrt(x-1)+2)+(2(x+5))/(sqrt(x^2-9)+8))=0
+)Với x>=3->1/(sqrt(x-1)+2)+(2(x+5))/(sqrt(x^2-9)+8)>0
->x-5=0
<=>x=5 (Tm-C)
Vậy : x=5 là nghiệm của phương trình