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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 10: Giải thích đầy đủ, chi tiết: `{(- ∞;1] ∪[5;+ ∞)} ∩{(- ∞;5] ∪[9;+ ∞)}`

Toán Lớp 10: Giải thích đầy đủ, chi tiết:
{(- ∞;1] ∪[5;+ ∞)} ∩{(- ∞;5] ∪[9;+ ∞)}

Comments ( 1 )

  1. Giải đáp:
    $ (-\infty;1] \cup \{5\}\cup [9;+\infty).$
    Lời giải và giải thích chi tiết:
    $A \cap (B \cup C)=(A \cap B) \cup (A \cap C)$
    Chứng minh:
    Lấy $x \in A \cap (B \cup C)$
    $\Rightarrow  \left\{\begin{array}{l} x \in A \\ x \in (B \cup C)\end{array} \right.\\ \Leftrightarrow   \left\{\begin{array}{l} x \in A \\ \left[\begin{array}{l} x \in B \\ x \in C\end{array} \right.\end{array} \right.\\ \Leftrightarrow  \left[\begin{array}{l} \left\{\begin{array}{l} x \in A \\ x \in B\end{array} \right.\\\left\{\begin{array}{l} x \in A \\ x \in C\end{array} \right.\end{array} \right.\\ \Leftrightarrow  x \in (A \cap B) \cup (A \cap C)\\ \Rightarrow A \cap (B \cup C) \subset (A \cap B) \cup (A \cap C)(1)$
    Lấy $x \in (A \cap B) \cup (A \cap C)$
    $\Leftrightarrow  \left[\begin{array}{l} \left\{\begin{array}{l} x \in A \\ x \in B\end{array} \right.\\\left\{\begin{array}{l} x \in A \\ x \in C\end{array} \right.\end{array} \right.\\ \Leftrightarrow   \left\{\begin{array}{l} x \in A \\ \left[\begin{array}{l} x \in B \\ x \in C\end{array} \right.\end{array} \right.\\ \Leftrightarrow  \left\{\begin{array}{l} x \in A \\ x \in (B \cup C)\end{array} \right.\\ \Leftrightarrow  x \in A \cap (B \cup C)\\ \Rightarrow   (A \cap B) \cup (A \cap C) \subset A \cap (B \cup C)(2)\\ (1)(2)\Rightarrow A \cap (B \cup C)=(A \cap B) \cup (A \cap C)$
    Áp dụng:
    $\Big((-\infty;1] \cup [5;+\infty)\Big) \cap \Big((-\infty;5] \cup [9;+\infty)\Big)\\ =\Bigg(\Big((-\infty;1] \cup [5;+\infty)\Big) \cap (-\infty;5] \Bigg) \cup \Bigg(\Big((-\infty;1] \cup [5;+\infty)\Big) \cap [9;+\infty) \Bigg)\\ = (-\infty;1] \cup \{5\}\cup [9;+\infty).$

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222-9+11+12:2*14+14 = ? ( )

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