Toán Lớp 8: 2x/x+3 : 8xy/x^2 + 3x
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Toán Lớp 8: 2x/x+3 : 8xy/x^2 + 3x
giải giúp mk vs
Comments ( 2 )
$\dfrac{2x}{x + 3}$ : $\dfrac{8xy}{x^2 + 3x}$
= $\dfrac{2x}{x + 3}$. $\dfrac{x^2 + 3x}{8xy}$
= $\dfrac{2x.x( x + 3)}{8xy(x + 3)}$
= $\dfrac{x}{4y}$
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(2x)/(x+3):(8xy)/(x^2+3x)
=(2x)/(x+3):(8xy)/(x(x+3))
=(2x)/(x+3):(8y)/(x+3)
=(2x)/(x+3)*(x+3)/(8y)
=(2x(x+3))/(8y(x+3))
=x/(4y)