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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: 6√a + 2/3√a/4 − a√9/a + √7 với a >0

Toán Lớp 9: 6√a + 2/3√a/4 − a√9/a + √7 với a >0

Comments ( 1 )

  1. Giải đáp:
    $\frac{10\sqrt[]{a}}{3} + \sqrt[]{7}$
    Lời giải và giải thích chi tiết:
    ĐKXĐ : $a > 0$
    Ta có :
    $6\sqrt[]{a} + \frac{2}{3}.\sqrt[]{\frac{a}{4}} – a.\sqrt[]{\frac{9}{a}} + \sqrt[]{7}$
    $= 6\sqrt[]{a} + \frac{2}{3}.\frac{\sqrt[]{a}}{2} – (\sqrt[]{a})^{2}.\frac{3}{\sqrt[]{a}} + \sqrt[]{7}$
    $= 6\sqrt[]{a} + \frac{\sqrt[]{a}}{3} – 3\sqrt[]{a} + \sqrt[]{7}$
    $= 3\sqrt[]{a} + \frac{\sqrt[]{a}}{3} + \sqrt[]{7}$
    $= \frac{10\sqrt[]{a}}{3} + \sqrt[]{7}$

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222-9+11+12:2*14+14 = ? ( )

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