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Toán Lớp 9: https://hoidap247.com/cau-hoi/2585990
Comments ( 1 )
$ BCDE$ nội tiếp $ => AEF = ABC $
$ BCE$ vuông $E$ mà $EM$ trung tuyến $ => MEC = ACB$
$ => PEM = FEM = 180^{0} – AEF – MEC $
$ = 180^{0} – ABC – ACB = BAC (2)$
$ (1) ; (2) => EDM = PEM $
$ => EDM$ đồng dạng $PEM (g.g)$ (chung góc $M$)