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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Phân tích nhân thức thành đa tử `a, 16x^{2} – 8x + 1 – 3 . (4x – 1)` `b, 27x^{3} + 8` `c, -16x^{4}y^{6} – 24x^{5}y^{5} – 9x^{6}y^{4}` `

Toán Lớp 8: Phân tích nhân thức thành đa tử
a, 16x^{2} – 8x + 1 – 3 . (4x – 1)
b, 27x^{3} + 8
c, -16x^{4}y^{6} – 24x^{5}y^{5} – 9x^{6}y^{4}
d, (ax + by)^{2} – (ay + bx)^{2}

Comments ( 2 )

  1. a)16x^2-8x+1-3.(4x-1)
    =(4x)^2-2.4x.1+1^2-3.(4x-1)
    =(4x-1)^2-3.(4x-1)
    =(4x-1)(4x-1-3)
    =(4x-1)(4x-4)
    b)27x^3+8
    =(3x)^3+2^3
    =(3x+2)(9x^2-6x+4)
    c)-16x^4y^6-24x^5y^5-9x^6y^4
    =-x^4y^4(16y^2+24xy+9x^2)
    =-x^4y^4[(4y)^2+2.(4y).(3x)+(3x)^2]
    =-x^4y^4.(4y+3x)^2
    d)(ax+by)^2-(ay+bx)^2
    =(ax+by-ay-bx)(ax+by+ay+bx)
    =[(ax-ay)-(bx-by)][(ax+ay)+(by+bx)]
    =[a(x-y)-b(x-y)][a(x+y)+b(x+y)]
    =(x-y)(a-b)(x+y)(a+b)

  2. Giải đáp+Lời giải và giải thích chi tiết:
    a) 16x^2 – 8x + 1 – 3.(4x – 1)
    = [(4x)^2 – 2.4x.1 + 1^2] – 3.(4x – 1)
    = (4x – 1)^2 – 3.(4x – 1)
    = (4x – 1)[(4x – 1) – 3]
    = (4x – 1)(4x – 1 – 3)
    = (4x – 1)(4x – 4)
    b) 27x^3 + 8
    = (3x)^3 + 2^3
    = (3x + 2)[(3x)^2 – 3x.2 + 2^2]
    = (3x + 2)(9x^2 – 6x + 4)
    c) – 16x^4 y^6 – 24x^5 y^5 – 9x^6 y^4
    = -x^4 y^4 . (16y^2 + 24xy + 9x^2)
    = -x^4 y^4 . [(4y)^2 + 2.4y.3x + (3x)^2]
    = -x^4 y^4 . (4y + 3x)^2
    d) (ax + by)^2 – (ay + bx)^2
    = (ax + by – ay – bx)(ax + by + ay + bx)
    = [(ax – ay) – (bx – by)][(ax + ay) + (by + bx)]
    = [a(x – y) – b(x – y)][a(x + y) + b( x + y)]
    = (x – y)(a – b)(x + y)(a + b)
    #SunHee

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222-9+11+12:2*14+14 = ? ( )

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