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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: (x + 3)(x^2 – 3x + 9) –x(x – 1)(x + 1) – 27 = 0

Toán Lớp 8: (x + 3)(x^2 – 3x + 9) –x(x – 1)(x + 1) – 27 = 0

Comments ( 2 )

  1. Giải đáp:
     
    Lời giải và giải thích chi tiết:
    => x^3+3^3-x(x^2-1^2)-27 = 0
    => x^3 + 27 – x^3 + x – 27 = 0
    => (x^3 – x^3) + (27-27) + x = 0
    => 0 + 0 + x = 0
    => x = 0

  2. Giải đáp:
    (x + 3) (x^2 − 3x + 9) − x (x − 1)(x + 1) − 27 = 0
    ⇔ x^3 + 27 − x (x^2 − 1) − 27 = 0
    ⇔ x^3 + 27 − x^3 + x − 27 = 0
    ⇔ x = 0

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222-9+11+12:2*14+14 = ? ( )

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