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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: rút gọn A= ((1/3 – căn 5)-(1/3+căn 5)) : căn 5

Toán Lớp 9: rút gọn A= ((1/3 – căn 5)-(1/3+căn 5)) : căn 5

Comments ( 2 )

  1. Giải đáp + Lời giải và giải thích chi tiết:
    A = (1/(3-\sqrt{5}) – 1/(3+\sqrt{5})) : \sqrt{5}
    = [ (3+\sqrt{5})/((3-\sqrt{5})(3+\sqrt{5})) – (3-\sqrt{5})/((3-\sqrt{5})(3+\sqrt{5})) ] . 1/\sqrt{5}
    = [ (3+\sqrt{5})/4 – (3-\sqrt{5})/4 ] . 1/\sqrt{5}
    = (3+\sqrt{5}-3+\sqrt{5})/4 . 1/\sqrt{5}
    = (2\sqrt{5})/4 . 1/\sqrt{5}
    = 2/4 = 1/2
     

  2. #tnvt
    A=[\frac{1}{3-\sqrt{5}}-\frac{1}{3+\sqrt{5}}]:\sqrt{5}
    =[\frac{3+\sqrt{5}}{(3-\sqrt{5})(3+\sqrt{5})}-\frac{3-\sqrt{5}}{(3-\sqrt{5})(3+\sqrt{5})}]:\sqrt{5}
    =[\frac{3+\sqrt{5}-(3-\sqrt{5})}{3^2-\sqrt{5}^2}]:\sqrt{5}
    =[\frac{3+\sqrt{5}-3+\sqrt{5}}{9-5}].\frac{1}{\sqrt{5}}
    =\frac{2\sqrt{5}}{4}.\frac{1}{\sqrt{5}}
    =\frac{\sqrt{5}}{2}.\frac{1}{\sqrt{5}}
    =\frac{\cancel{\sqrt{5}}}{2}.\frac{1}{\cancel{\sqrt{5}}}
    =1/2

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222-9+11+12:2*14+14 = ? ( )

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