Toán Lớp 9: Rút gọn
$\frac{3√2-6}{√2-1}$ +$\frac{6√2-4}{√3-2}$
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Toán Lớp 9: Rút gọn
$\frac{3√2-6}{√2-1}$ +$\frac{6√2-4}{√3-2}$
Comments ( 1 )
\dfrac{{3\sqrt 2 – 6}}{{\sqrt 2 – 1}} + \dfrac{{6\sqrt 2 – 4}}{{\sqrt 3 – 2}}\\
= \dfrac{{\left( {3\sqrt 2 – 6} \right)\left( {\sqrt 2 + 1} \right)}}{{2 – 1}} + \dfrac{{\left( {6\sqrt 2 – 4} \right)\left( {\sqrt 3 + 2} \right)}}{{3 – 4}}\\
= 3.2 + 3\sqrt 2 – 6\sqrt 2 – 6 – \left( {6\sqrt 6 + 12\sqrt 2 – 4\sqrt 3 – 8} \right)\\
= 6 – 3\sqrt 2 – 6 – 6\sqrt 6 – 12\sqrt 2 + 4\sqrt 3 + 8\\
= 8 – 15\sqrt 2 – 6\sqrt 6 + 4\sqrt 3
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