Toán Lớp 11: lim 5 bình 4 n bình / 7n + 9n bình
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Toán Lớp 11: lim 5 bình 4 n bình / 7n + 9n bình
Comments ( 1 )
Giải đáp: $\dfrac{4}{9}$
Lời giải và giải thích chi tiết:
$\begin{array}{l}
\lim \dfrac{{5n + 4{n^2}}}{{7n + 9{n^2}}}\\
= \lim \dfrac{{\dfrac{{5n}}{{{n^2}}} + \dfrac{{4{n^2}}}{{{n^2}}}}}{{\dfrac{{7n}}{{{n^2}}} + \dfrac{{9{n^2}}}{{{n^2}}}}}\\
= \lim \dfrac{{\dfrac{5}{n} + 4}}{{\dfrac{7}{n} + 9}}\\
= \dfrac{4}{9}
\end{array}$