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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 7: Cho A= 3+3²+3³+3⁴+-+3¹⁰⁰ Chứng tỏ A chia hết cho 4

Toán Lớp 7: Cho A= 3+3²+3³+3⁴+….+3¹⁰⁰
Chứng tỏ A chia hết cho 4

Comments ( 2 )

  1. Giải: 
    A = 3 + 3^2 + 3^3 + 3^4 + … + 3^100
    A = (3 + 3^2) + (3^3 + 3^4) + … + (3^99 + 3^100)
    A = 3.(1 + 3) + 3^2.(1 + 3) + … + 3^99.(1 + 3)
    A = 3.4 + 3^2 . 4 + … + 3^99.4
    A = 4.(3 + 3^2 + … + 3^99) \vdots 4
    Vậy A \vdots 4

  2. A=3+3^2+3^3+3^4+…+3^100
    =(3+3^2)+(3^3+3^4)+…+(3^99+3^100)
    =3(1+3)+3^3(1+3^2)+…+3^99(1+3)
    =(1+3)(3+3^2+3^3+…+3^99)
    =4.(3+3^2+3^3+…+3^99)
    Vì 4\vdots4
    Nên 4.(3+3^2+3^3+…+3^99)\vdots4 
    =>A\vdots4
     

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222-9+11+12:2*14+14 = ? ( )

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