Toán Lớp 8: Tìm x
( 3x -1 )(2x + 7) – ( x+1) (6x-50) = 16
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Toán Lớp 8: Tìm x
( 3x -1 )(2x + 7) – ( x+1) (6x-50) = 16
Comments ( 2 )
(3x – 1)(2x + 7) – (x + 1)(6x – 5) = 16\\
\Rightarrow (6x + 21x – 2x – 7) – (6x – 5x + 6x – 50) – 16 = 0\\
\Rightarrow 6x + 19x – 7 – 6x – x + 50 – 16 = 0\\
\Rightarrow 18x + 27 = 0\\
\Rightarrow 18x = – 27\\
\Rightarrow x = \frac{{ – 3}}{2}\\
\Rightarrow S \in \{ \frac{{ – 3}}{2}\}
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