Toán Lớp 8: Thành nhân tử.
x^2+7x^3
5x^3-10x^2y+5xy^2-5xz^2
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Toán Lớp 8: Thành nhân tử.
x^2+7x^3
5x^3-10x^2y+5xy^2-5xz^2
Comments ( 2 )
Giải đáp + Lời giải và giải thích chi tiết:
a, $x^{2}$ + $7x^{3}$
= $\text{x}$$^{2}$ $\text{( 1 + 7x )}$
b, $\text{5}$$x^{3}$ – $\text{10x}$$^{2}$$\text{y + 5xy}$$^{2}$ – $\text{5xz}$$^{2}$
= $\text{5x ( $x^{2}$ – 2xy + y}$ $^{2} + z^{2} )$
= $\text{5x ( x – y )}$$^{2}$ – $z^{2}$
= $\text{5x ( x – y – z ) ( x – y + z )}$
$x^2+7x^3$
$=x^2+7xx^2$
$=x^2\left(1+7x\right)$
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$5x^3-10x^2y+5xy^2-5xz^2$
$=5x\left(x^2-2xy+y^2-z^2\right)$
=5x.(x-y)^2 -z^2
=5 x (x – y – z) (x – y + z)