Toán Lớp 8: x2+ 5y2 – 4x – 4xy + 6y +5 =0
Tìm x, y
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Toán Lớp 8: x2+ 5y2 – 4x – 4xy + 6y +5 =0
Tìm x, y
Comments ( 1 )
Chúc bạn học tốt nha! :))
underlineoverline{haianh28907}
x^2 + 5y^2 – 4x – 4xy + 6y + 5 = 0
(x^2 + 4y^2 + 4 – 4x + 8y – 4xy) + (y^2 – 2y + 1) = 0
(x^2 + (2y)^2 + 2^2 – 2x.2 + 2.2y.2 – 2.x.2y) + (y^2 – 2y + 1) = 0
(x-2y-2)^2 + (y-1)^2 = 0
text{Ta có:}{((x-2y-2)^2>=0),((y-1)^2>=0):}
-> {((x-2y-2)^2=0),((y-1)^2=0):}
-> {(y-1=0 <=> y = 1),(x-2y-2=0 -> x-2-2=x-4=0 <=> x=4):}
text{Vậy x = 4, y = 1 thỏa mãn biểu thức trên.}