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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: tông 3 mu1+ 3 mu2 +3 mu3 +3 mu4+3 mu5+…+3 mu2012

Toán Lớp 6: tông 3 mu1+ 3 mu2 +3 mu3 +3 mu4+3 mu5+…+3 mu2012

Comments ( 2 )

  1. Giải đáp:
    (3^2013-3)/2
    Lời giải và giải thích chi tiết:
    -Đặt A = 3^1 + 3^2 +3^3+3^4+3^5+………..+3^2012
    => 3A = 3^2+3^3+3^4 +3^5+3^6+………..+3^2013
    => 3A-A=3^2013-3^1
    => 2A=3^2013-3
    => A=(3^2013-3)/2
     

  2. Answer
    $\text{Đặt}$ 3^{1} + 3^{2} + 3^{3} + … + 3^{2012} $\text{là A}$
    A = 3^{1} + 3^{2} + 3^{3} + … + 3^{2012}
    3A = 3 . (3^{1} + 3^{2} + 3^{3} + … + 3^{2012})
    3A = 3^{2} + 3^{3} + 3^{4} + … + 3^{2013}
    3A – A = (3^{2} + 3^{3} + 3^{4} + … + 3^{2013}) – (3^{1} + 3^{2} + 3^{3} + … + 3^{2012})
    2A = 3^{2013} – 3
    A = {3^{2013} – 3}/2
    $\text{Vậy}$ 3^{1} + 3^{2} + 3^{3} + … + 3^{2012} = {3^{2013} – 3}/2

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222-9+11+12:2*14+14 = ? ( )

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