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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Tính nhân phân thức a)2x²-20x+50/3x+3. x²-1/4(x-5)³ b)(x²-xy)²/x²-y². x³+y³/x³y-x²y²-xy³

Tháng Sáu 2, 2022 Toán học 1 Comment 0 views

Toán Lớp 8: Tính nhân phân thức
a)2x²-20x+50/3x+3. x²-1/4(x-5)³
b)(x²-xy)²/x²-y². x³+y³/x³y-x²y²-xy³

Comments ( 1 )

  1. aivilanlan
    aivilanlan
    2 Tháng Sáu, 2022 at 8:44 chiều
    Reply
    Gửi bạn:
    $a,$ $\dfrac{2x^2-20x+50}{3x+3}.\dfrac{x^2-1}{4(x-5)^3}$ 
    $=\dfrac{2(x^2-10x+25)}{3(x+1)}.\dfrac{(x-1)(x+1)}{4(x-5)^3}$ 
    $=\dfrac{2(x-5)^2}{3(x+1)}.\dfrac{(x-1)(x+1)}{4(x-5)^3}$ 
    $=\dfrac{(x-5)^2}{3}.\dfrac{x-1}{2(x-5)^3}$ 
    $=\dfrac{1}{3}.\dfrac{x-1}{2(x-5)}$ 
    $=\dfrac{x-1}{6(x-5)}$ 
    $=\dfrac{x-1}{6x-30}$ 
    $b,$ $\dfrac{(x^2-xy)^2}{x^2-y^2}.\dfrac{x^3+y^3}{x^3y-x^2y^2-xy^3}$ 
    $=\dfrac{x(x-y)^2}{(x-y)(x+y)}.\dfrac{(x+y)(x^2-xy+y^2)}{xy(x^2-xy+y^2}$ 
    $=\dfrac{x(x-y)}{x+y}.\dfrac{x+y}{xy}$ 
    $=\dfrac{x(x-y)}{1}.\dfrac{1}{xy}$ 
    $=\dfrac{x(x-y)}{xy}$ 
    $=\dfrac{x-y}{y}$ 
     

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222-9+11+12:2*14+14 = ? ( )

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