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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: so sánh 1+2+2^2+…+20 và 9.2^18

Toán Lớp 6: so sánh 1+2+2^2+…+20 và 9.2^18

Comments ( 2 )

  1. Giải đáp:
    $1+2+2^2\ +\,.\!.\!.+\ 2^{20}<9.2^{18}$.
    Lời giải và giải thích chi tiết:
    $A=1+2+2^2\ +\,.\!.\!.+\ 2^{20}\\\Rightarrow 2A=2.(1+2+2^2\ +\,.\!.\!.+\ 2^{20})\\\Rightarrow 2A=2+2^2+2^3\ +\,.\!.\!.+\ 2^{21}\\\Rightarrow 2A-A=(2+2^2+2^3\ +\,.\!.\!.+\ 2^{21})-(1+2+2^2\ +\,.\!.\!.+\ 2^{20})\\\Rightarrow A=2^{21}-1\\\Rightarrow 2^{21}-1<2^{21}=2^3.2^{18}=8.2^{18}\\\Rightarrow 2^{21}-1<8.2^{18}<9.2^{18}\\\Rightarrow \texttt{Biểu thức}<9.2^{18}$

  2. ~~ Bạn tham khảo ~~
    Đặt A = 1 + 2 + 2^2 + …. + 2^20
    => 2A = 2 + 2^2 + 2^3 + … + 2^21
    => 2A – A = (2 + 2^2 + 2^3 + … + 2^21) – ( 1 + 2 + 2^2 + …. + 2^20)
    => A = 2^21 – 1
    => A = 2^18 . 2^3 – 1
    => A = 2^18 . 8 – 1 < 9 . 2^18
    Vậy 1 + 2 + 2^2 + …. + 2^20 < 9 . 2^18

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222-9+11+12:2*14+14 = ? ( )

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