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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: help meeeeeee $\frac{4}{2x+8}$ +$\frac{3}{x^2-16}$

Toán Lớp 8: help meeeeeee
$\frac{4}{2x+8}$ +$\frac{3}{x^2-16}$

Comments ( 2 )

  1. Giải đáp:
     
    Lời giải và giải thích chi tiết:
     4/[2x+8] + 3/[x^2 -16]
    = 4/[2(x+4)] +3/[(x-4)(x+4)]
    =[ 4(x-4)]/[2(x-4)(x+4)] +[3.2]/[2(x-4)(x+4)]
    =[4x-16+6]/[2(x-4)(x+4)]
    =[4x-10]/[2(x^2 -16)]
    =[2(2x-5)]/[2(x^2 -16)]
    =[2x-5]/[x^2 -16]
    (bài tham khảo)

  2. $\text{$\dfrac{4}{2x + 8}$ + $\dfrac{3}{x² – 16}$ Đkxđ: x $\neq$ ±4 }$
    $\text{= $\dfrac{4}{2(x + 4)}$ + $\dfrac{3}{(x – 4)(x + 4)}$}$
    $\text{= $\dfrac{2}{x + 4}$ + $\dfrac{3}{(x – 4)(x + 4)}$ }$
    $\text{= $\dfrac{2.(x – 4) + 3}{(x – 4)(x + 4)}$}$
    $\text{= $\dfrac{2x – 8 + 3}{(x – 4)(x + 4)}$ }$
    $\text{= $\dfrac{2x – 5}{(x – 4)(x + 4)}$ }$
    $\textit{Ha1zzz}$
     

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222-9+11+12:2*14+14 = ? ( )

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