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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: $\text{Tìm n ∈ N biết n+6 ⋮ n+1}$

Toán Lớp 6: $\text{Tìm n ∈ N biết n+6 ⋮ n+1}$

Comments ( 2 )

  1. n + 6 \vdots n + 1
    => (n + 1) + 5 \vdots n + 1
    => n + 1 \vdots n + 1
    => n +6 \vdots n + 1
    => 5 \vdots n + 1
    => x + 1 ∈ Ư(5) = {1;5}
    => x ∈ {0;4}
    Vậy x ∈ {0;4}

  2. Vì: n+6 chia hết cho n+1 nên
    ⇒ n+6 →B(n+1)
    ⇒B(n+1)={1;2;3;6}
    +) n+1=1=1-1=0
    +) n+1=2=2-1=1
    +) n+1=3=3-1=2
    +) n+3=6=6-3=3
    Vậy n là: 0;1;2;3

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222-9+11+12:2*14+14 = ? ( )

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