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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Rút gọn `Q = ((2x+1)/(x^2 – 5x) – 2x/(x^2 + 5x)). (x^3 – 25x)/(21x-2)` $( x \neq 0 , x \neq ±5, x \neq$ `2/21)`

Toán Lớp 8: Rút gọn Q = ((2x+1)/(x^2 – 5x) – 2x/(x^2 + 5x)). (x^3 – 25x)/(21x-2) $( x \neq 0 , x \neq ±5, x \neq$ 2/21)

Comments ( 2 )

  1. Giải đáp:
     (21x+5)/(21x-2)
    Lời giải và giải thích chi tiết:
    Q=((2x+1)/(x^2-5x)-(2x)/(x^2+5x)). (x^3-25x)/(21x-2)
    =((2x+1)/(x^2-5x)-(2x)/(x(x+5))). (x(x^2-25))/(21x-2)
    =((2x+1)/(x^2-5x)- 2/(x+5)) . (x(x-5)(x+5))/(21x-2)
    =((x+5)(2x+1)-2(x^2-5x))/((x^2-5x)(x+5)) . (x(x-5)(x+5))/(21x-2)
    =(2x^2+x+10x+5-2x^2+10x)/(x(x-5)) . (x(x-5))/(21x-2)
    =(21x+5) . 1/(21x-2)
    =(21x+5)/(21x-2)

  2. Gửi bạn:
    $Q=(\dfrac{2x+1}{x^2-5x}-\dfrac{2x}{x^2+5x}).\dfrac{x^3-25x}{21x-2}$ 
    $Q=(\dfrac{2x+1}{x(x-5)}-\dfrac{2x}{x(x+5)}).\dfrac{x^3-25x}{21x-2}$ 
    $Q=(\dfrac{(2x+1)(x+5)}{x(x-5)(x+5)}-\dfrac{2x(x-5)}{x(x+5)(x-5)}).\dfrac{x^3-25x}{21x-2}$ 
    $Q=(\dfrac{2x^2+11x+5}{x(x-5)(x+5)}-\dfrac{2x^2-10x}{x(x+5)(x-5)}).\dfrac{x^3-25x}{21x-2}$ 
    $Q=(\dfrac{2x^2+11x+5-2x^2+10x}{x(x-5)(x+5)}).\dfrac{x^3-25x}{21x-2}$ 
    $Q=\dfrac{21x+5}{x(x-5)(x+5)}.\dfrac{x(x-5)(x+5)}{21x-2}$ 
    $Q=\dfrac{21x+5}{21x-2}$ 

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222-9+11+12:2*14+14 = ? ( )