Toán Lớp 8: Tìm a sao cho x^2 -ax+3 chi hết cho x-2
Leave a reply
Register Now
Login
Lost Password
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Toán Lớp 8: Tìm a sao cho x^2 -ax+3 chi hết cho x-2
Comments ( 2 )
x^2 -ax+3: x-2 = x+2-a ( dư 7-2a)
$⇒ Để$ x^2 -ax+3 chia hết cho x-2 $thì$ x^2 -ax+3: x-2 $dư$ 0
$⇒ 7-2a=0$
$⇔ 7-2a=0$
$⇔ 2a=7$
⇔ a=7/2
Vậy $với$ a=7/2 thì x^2 -ax+3 $chia$ hết cho x-2