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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: a. $\frac{3x+10}{7xy}$ – $\frac{10-2x}{7xy}$ b. $\frac{2x+5}{3}$ – $\frac{2-x}{3}$ c. $\frac{x+6}{2x+6}$ – $\frac{2x+3}{x(x+3)}

Home/ Toán Lớp 8: a. $\frac{3x+10}{7xy}$ – $\frac{10-2x}{7xy}$ b. $\frac{2x+5}{3}$ – $\frac{2-x}{3}$ c. $\frac{x+6}{2x+6}$ – $\frac{2x+3}{x(x+3)}

Toán Lớp 8: a. $\frac{3x+10}{7xy}$ – $\frac{10-2x}{7xy}$ b. $\frac{2x+5}{3}$ – $\frac{2-x}{3}$ c. $\frac{x+6}{2x+6}$ – $\frac{2x+3}{x(x+3)}

Tháng Tư 2, 2022 Toán học 1 Comment 0 views

Toán Lớp 8: a. $\frac{3x+10}{7xy}$ – $\frac{10-2x}{7xy}$
b. $\frac{2x+5}{3}$ – $\frac{2-x}{3}$
c. $\frac{x+6}{2x+6}$ – $\frac{2x+3}{x(x+3)}$

Comments ( 1 )

  1. thucquyenlan
    thucquyenlan
    2 Tháng Tư, 2022 at 10:38 chiều
    Reply
    Giải đáp+Lời giải và giải thích chi tiết:
    a)
    (3x+10)/(7xy)-(10-2x)/(7xy)
    =[3x+10-(10-2x)]/(7xy)
    =(3x+10-10+2x)/(7xy)
    =[(3x+2x)+(10-10)]/(7xy)
    =(5x)/(7xy)
    =(5)/(7y)
    b)
    (2x+5)/(3)-(2-x)/(3)
    =[2x+5-(2-x)]/(3)
    =(2x+5-2+x)/(3)
    =[(2x+x)+(5-2)]/(3)
    =(3x+3)/(3)
    =[3(x+1)]/(3)
    =(x+1)/(1)
    =x+1
    c)
    (x+6)/(2x+6)-(2x+3)/[x(x+3)]
    =(x+6)/(2(x+3)]-(2x+3)/[x(x+3)]
    =[x(x+6)]/[2x(x+3)]-[2(2x+3)]/[2x(x+3)]
    =(x^2+6x)/[2x(x+3)]-(4x+6)/[2x(x+3)]
    =[x^2+6x-(4x+6)]/[2x(x+3)]
    =(x^2+6x-4x-6)/[2x(x+3)]
    =[x^2+(6x-4x)-6]/[2x(x+3)]
    =(x^2+2x-6)/[2x(x+3)]
    =(x^2+2x-6)/(2x^2+6x)
    $\text{#LinhSad}$

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222-9+11+12:2*14+14 = ? ( )

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