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Toán Lớp 6: 198:[130-(27-19)]+2021^0 5^20:(5^15.15+5^15.10) 3x+27=45 35-5(x-1)=10 4.2^x-3=125

Home/ Toán Lớp 6: 198:[130-(27-19)]+2021^0 5^20:(5^15.15+5^15.10) 3x+27=45 35-5(x-1)=10 4.2^x-3=125

Toán Lớp 6: 198:[130-(27-19)]+2021^0 5^20:(5^15.15+5^15.10) 3x+27=45 35-5(x-1)=10 4.2^x-3=125

Nhã Trúc Tháng Ba 18, 2022 Toán học 1 Comment 0 views

Toán Lớp 6: 198:[130-(27-19)]+2021^0
5^20:(5^15.15+5^15.10)
3x+27=45
35-5(x-1)=10
4.2^x-3=125

Comments ( 1 )

thienthanh
18 Tháng Ba, 2022 at 10:05 chiều

Reply

a)

198 : [ 130 – ( 27 – 19 ) ] + 2021^0

= 198 : [ 130 – 8 ] + 1

= 198 : 122 + 1

= 99/61 + 1

= 160/61

b)

5^20 : ( 5^15 × 15 + 5^15 × 10 )

= 5^20 : [ 5^15 × ( 15 + 10 ) ]

= 5^20 : [ 5^15 × 25 ]

= 5^20 : [ 5^15 ×× 5^2 ]

= 5^20 : 5^17

= 5^3 = 125

c)

3x + 27 = 45

3x = 45 – 27

3x = 18

x = 18 : 3

x = 6

d)

35 – 5( x – 1 ) = 10

5( x – 1 ) = 35 – 10

5( x – 1 ) = 25

x – 1 = 25 : 5

x – 1 = 5

x = 5 + 1

x = 6

e)

4 × 2^x – 3 = 125

4 × 2^x = 125 + 3

4 × 2^x = 128

2^x = 128 : 4

2^x = 32

2^x = 2^5

x = 5

@Tina

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