Toán Lớp 6: a)2022-[10.(4^3-56):2^3+2^3].2021^0 b)500-{5[409-2^3-21)^2]+10^3}:15 c)[(18^7:18^6-17).2021-1989.17.1^2020-13^2.2022^0 HELP ME =((

Question

Toán Lớp 6:  a)2022-[10.(4^3-56):2^3+2^3].2021^0 b)500-{5[409-2^3-21)^2]+10^3}:15 c)[(18^7:18^6-17).2021-1989.17.1^2020-13^2.2022^0  HELP ME =((

tuyetanhthu · Answer

a)2022-[10.(4&sup3; - 56):2&sup3;+2&sup3;].$2021^{0}$    =2022-[10.(64-56):2&sup3;+2&sup3;].1   =2022-[10.8:2&sup3;+2&sup3;]   =2022-[10.8:8+8]   =2022-[80:8+8]   =2022-[10+8]   =2022-18   =2004   b)500-{5[(409-2&sup3;-21)&sup2;  ]+  10&sup3;}:15   =500-{5[(409-8-21)&sup2;]+10&sup3;}:15    =500-{5.[(409-8-21)&sup2;]+10&sup3;} : 15   =500-{5.380&sup2;+10&sup3;}:15   =500-{5.144400+1000}:15   =500-{722000 + 1000} : 15   =500-723000 : 15   =500-48200   =-47700   c)($18^{7}$:$18^{6}$-17).2021-1989.17.$1^{2020}$-$13^{2}$.$2022^{0}$   =(18-17).2021-1989.17.$1^{2020}$-$13^{2}$.$2022^{0}$   =1.2021-1989.17.$1^{2020}$-$13^{2}$.$2022^{0}$   =1.2021-1989.17.1-169.1   =1 .2021-1989.17.1-169. 1   =2021-1989.17-169   =2021-33813-169   =-31961   Xin c&acirc;u trả lời hay nhất #21kamehameha

cattien · Answer

Ron     a, 2022 - [10 . ($4^{3}$ - 56) : $2^{3}$ + $2^{3}$] . $2021^{0}$     = 2022 - [10 . (64 - 56) : 8 + 8] . 1      = 2022 - [10 . 8 : 8 + 8]     = 2022 - [80 : 8 + 8]       = 2022 - [10 + 8]     = 2022 - 18     = 2004     b, 500 - {5 [409 - $2^{3}$ - 21)$^{2}] + $10^{3}$} : 15       = 500 - {5 [409 - 8 - 21)$^{2}$ + 1000} : 15      = 500 - {5 . $380^{2}$ + 1000} : 15     = 500 - {5 . 1 44400 + 1000} : 15       = 500 - {722000 + 1000} : 15       = 500 - 723000 : 15       = 500 - 48200       = -47700       c, ($18^{7}$ : $18^{6}$ - 17) . 2021 - 1989 . 17 . $1^{2020}$ - $13^{2}$ . $2022^{0}$        = (18 - 17) . 2021 - 1989 . 17 . 1 - 169 . 1       = 1 . 2021 - 1989 . 17 . 1 - 169 . 1       = 2021 - 1989 . 17 - 169       = 2021 - 33813 - 169       = -31961         #Ch&uacute;c bạn học tốt        Xin hay nhất