Toán Lớp 8: Giari phương trình
$\frac{x}{3}$ $+$ $\frac{2x-1}{6}$ = $1 -$$\frac{x}{3}$
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Toán Lớp 8: Giari phương trình
$\frac{x}{3}$ $+$ $\frac{2x-1}{6}$ = $1 -$$\frac{x}{3}$
Comments ( 1 )
\dfrac{x}{3} + \dfrac{{2x – 1}}{6} = 1 – \dfrac{x}{3}\\
\Leftrightarrow \dfrac{x}{3} + \dfrac{{2x}}{6} – \dfrac{1}{6} + \dfrac{x}{3} = 1\\
\Leftrightarrow \left( {\dfrac{1}{3} + \dfrac{1}{3} + \dfrac{1}{3}} \right).x = 1 + \dfrac{1}{6}\\
\Leftrightarrow x = \dfrac{7}{6}\\
Vậy\,x = \dfrac{7}{6}
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