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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 10: Cho |$\overrightarrow{a}$|=3 ; |$\overrightarrow{b}$|=4 ($\overrightarrow{a}$ ; $\overrightarrow{b}$)=$60^o$ Tính |3$\overrightarrow{a

Toán Lớp 10: Cho |$\overrightarrow{a}$|=3 ; |$\overrightarrow{b}$|=4
($\overrightarrow{a}$ ; $\overrightarrow{b}$)=$60^o$
Tính |3$\overrightarrow{a}$+2 $\overrightarrow{b}$|

Comments ( 1 )

  1.  Ta có: |3vec(a) +2\vec(b)|^2 =(3\vec(a))^2 +12\vec(a).\vec(b) +(2\vec(b))^2
                                   = 9a^2+4b^2+12.|\vec(a)|.|\vec(b)|.cos(\vec(a);\vec(b))
                                    =9.3^2 + 2.4^2+12.3.2.cos60^0 =149
    \Rightarrow |3\vec(a)+2\vec(b)| = \sqrt(149)

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222-9+11+12:2*14+14 = ? ( )

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