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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 6: 15 `\vdots` ( x – 3 ) ( x + 22 ) `\vdots` ( x – 7 ) ( 3x + 2 ) `\vdots` ( x + 1 )

Tháng Hai 19, 2022 Toán học 1 Comment 0 views

Toán Lớp 6: 15 \vdots ( x – 3 )
( x + 22 ) \vdots ( x – 7 )
( 3x + 2 ) \vdots ( x + 1 )

Comments ( 1 )

  1. minhhaanh
    minhhaanh
    19 Tháng Hai, 2022 at 8:20 chiều
    Reply
    a, 
    Ta có: 15 vdots (x – 3)
    => x – 3 in Ư(15) = {±1;±3;±5;±15}
    => x in {4;2;6;0;8;-2;18;-12}
    Vậy x in {-12;-2;0;2;4;6;8;18}
    b,
    Ta có: (x + 22) vdots x – 7
    => (x – 7) + 29 vdots (x – 7)
    => 29 vdots x – 7
    => x – 7 in Ư(29) = {±1;±29}
    => x in {8;6;36;-22}
    Vậy x in {-22;6;8;36}
    c,
    Ta có: 3x + 2 vdots x + 1
    => 3(x + 1) – 1 vdots x + 1
    => 1 vdots x + 1
    => x + 1 in Ư(1) = {±1}
    => x in {0;-2}
    Vậy x in {-2;0}
     

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222-9+11+12:2*14+14 = ? ( )

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