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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 8: Giải PT (x^2 -1)(x+2)(x-3)=(x-1)(x^2 -4)(x+5)

Home/ Toán Lớp 8: Giải PT (x^2 -1)(x+2)(x-3)=(x-1)(x^2 -4)(x+5)

Toán Lớp 8: Giải PT (x^2 -1)(x+2)(x-3)=(x-1)(x^2 -4)(x+5)

Tháng Hai 19, 2023 Toán học 1 Comment 0 views

Toán Lớp 8: Giải PT
(x^2 -1)(x+2)(x-3)=(x-1)(x^2 -4)(x+5)

Comments ( 1 )

  1. dananhnhu2k4
    dananhnhu2k4
    19 Tháng Hai, 2023 at 11:21 sáng
    Reply
    $\text{(x² -1)(x+2)(x-3)=(x-1)(x² -4)(x+5)}$
    $\text{⇔(x-1)(x+1)(x+2)(x-3)-(x-1)(x-2)(x+2)(x+5)=0}$
    $\text{⇔(x-1)(x+2)[(x+1)(x-3)-(x-2)(x+5)]=0}$
    $\text{⇔(x-1)(x+2)[(x²-2x-3)-(x²+3x-10)]=0}$
    $\text{⇔(x-1)(x+2)[x²-2x-3-x²-3x+10]=0}$
    $\text{⇔(x-1)(x+2)[-5x+7]=0}$
    $\text{⇔x-1=0 ⇔x=1}$
    $\text{x+2=0⇔x=-2}$
    $\text{-5x+7=0⇔-5x=-7⇔x=$\frac{7}{5}$}$ 

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222-9+11+12:2*14+14 = ? ( )

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