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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: chứng minh a^3+b^3+c^3=3abc nếu a+b+c=0

Toán Lớp 9: chứng minh a^3+b^3+c^3=3abc nếu a+b+c=0

Comments ( 2 )

  1. nếu a+b+c=0
    ⇔a+b=-c
    ⇔(a+b)³=-c³
    ⇔a³+b³+3ab(a+b)=-c³
    ⇔a³+b³+c³=-3ab(a+b)=3abc (do c=-(a+b))
    ⇔dpcm
    chuc bạn hoc tốt
     

  2.  $a+b+c=0$
    $⇔ (a+b+c)^3=0$
    $⇔ a^3+b^3+c^3+3ab(a+b+c)+3ac(a+b+c)+3bc(a+b+c)-3abc=0$
    $⇔ a^3+b^3+c^3-3abc=0$
    $⇔ a^3+b^3+c^3=3abc$ (đpcm)

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222-9+11+12:2*14+14 = ? ( )

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