Toán Lớp 9: Đề: giải phương trình:
$\sqrt{2x + 3}$ $=$ $5.$ ($”$Căn 2x + 3$”$ = 5
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Toán Lớp 9: Đề: giải phương trình:
$\sqrt{2x + 3}$ $=$ $5.$ ($”$Căn 2x + 3$”$ = 5
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Answer
\sqrt{2x + 3} = 5 (Đk : x >= 3/2)
<=> 2x + 3 = 5^2
<=> 2x + 3 = 25
<=> 2x = 25 – 3
<=> 2x = 22
<=> x = 22 : 2
<=> x = 11 (TMĐK)
Vậy S = {11}