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222-9+11+12:2*14+14 = ? ( )

Toán Lớp 9: 2- √3 /1+ √4+2 √3 + 2+ √3 / 1- √4-2 √3

Toán Lớp 9: 2- √3 /1+ √4+2 √3 + 2+ √3 / 1- √4-2 √3

Comments ( 1 )

  1. $\begin{array}{l} \dfrac{{2 – \sqrt 3 }}{{1 + \sqrt {4 + 2\sqrt 3 } }} + \dfrac{{2 + \sqrt 3 }}{{1 – \sqrt {4 – 2\sqrt 3 } }}\\  = \dfrac{{2 – \sqrt 3 }}{{1 + \sqrt {{{\left( {\sqrt 3  + 1} \right)}^2}} }} + \dfrac{{2 + \sqrt 3 }}{{1 – \sqrt {{{\left( {\sqrt 3  – 1} \right)}^2}} }}\\  = \dfrac{{2 – \sqrt 3 }}{{2 + \sqrt 3 }} + \dfrac{{2 + \sqrt 3 }}{{2 – \sqrt 3 }}\\  = \dfrac{{{{\left( {2 – \sqrt 3 } \right)}^2} + {{\left( {2 + \sqrt 3 } \right)}^2}}}{{4 – 3}}\\  = \dfrac{{4 + 3 + 4 + 3 – 4\sqrt 3  + 4\sqrt 3 }}{1} = 14 \end{array}$  

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222-9+11+12:2*14+14 = ? ( )